数学题：三只猴子吃篮子里的桃子，第一只猴子吃了1/3，第二只猴子吃了剩下的1/3，第三只猴子吃了第二只猴子吃过后剩下的1/4，最后篮子里还剩下6个桃子。篮子里原来有桃子多少个？

数学题解答：先弄清每只猴子吃了篮子里所有桃子的几分之几。

第一只：1/3

第二只：（1　-　1/3）×　1/3＝2/9

第三只：（1　-　1/3　-　2/9）×　1/4　＝　1/9

剩下的6个桃子占总数的几分之几：1　-　1/3　-　2/9　-　1/9　＝1/3

桃子的总数：6　÷　1/3　＝18（个）

答：篮子里原来有桃子18个。

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