两瓶香水甲瓶用去九分之五

  • 时间:2020-06-10 18:36:27
  • 分类:数学世界
  • 阅读:159 次

两瓶香水的数学问题,这是群中“超越自我”同学提出的问题:两瓶香水,甲瓶用去九分之五(5/9),乙瓶用去六分之一(1/6),两瓶剩下的水相等,用之前甲瓶是乙瓶的几分之几?

ziyo老师数学题解答:甲瓶用去5/6,应该剩下1-5/9=4/9;乙瓶用去1/6,应该剩下1-1/6=5/6。此时两瓶中剩下的相等,但我们可以看出,剩下的份数并不一致,甲瓶中剩下的份数是4(即4/9的分子),乙瓶中剩下的份数是5(即5/6的分子),所以应该让它们的份数一致,可以根据分数的基本性质,让这两个分数的分子变成相同的。即4/9=20/45,5/6=20/24。

此时通过分母可以看出,甲瓶中原有45份,而乙瓶中原有24份。所以甲瓶占乙瓶的:45÷24=15/8,问题得以解决。

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