“神马都是浮云”同学问：(1/6+1/7+1/8)×(1/7+1/8+1/9)-(1/6+1/7+1/8+1/9)×(1/7+1/8)怎么计算？第二种问法，请问一下各位：（6分之1+7分之1+8分之1）*（7分之1+8分之1+9分之1）—（6分之1+7分之1+8分之1+9分之1)*（7分之1+8分之1）这道算式等于多少啊？应该有简便算法吧！有老师能告诉我方法吗？

数学题解答：此题算式较长，其中有些部分为几个分数相加，且多次出现，故可以用换元法来解决。设1/6+1/7+1/8＝a，则原式变成：

=（1/7+1/8+1/9）a-(a+1/9)×(1/7+1/8)

=(1/7+1/8+1/9)a-(1/7+1/8)a-(1/7+1/8)×1/9

=1/9a-(1/7+1/8)×1/9

此时再将a换回，变成1/6+1/7+1/8，这样算式又变成了：

=(1/6+1/7+1/8)×1/9-(1/7+1/8)×1/9

=1/6×1/9

=1/54

至此，已算出得数，主要用了换元法和乘法分配律解决了这个问题。

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