SQL Inner Join Tutorial with Example: Managers with at Least 5 D
- 时间:2020-10-05 13:15:44
- 分类:网络文摘
- 阅读:135 次
Given the following SQL Schema:
Create table If Not Exists Employee (Id int, Name varchar(255), Department varchar(255), ManagerId int)
Truncate table Employee
insert into Employee (Id, Name, Department, ManagerId) values ('101', 'John', 'A', 'None')
insert into Employee (Id, Name, Department, ManagerId) values ('102', 'Dan', 'A', '101')
insert into Employee (Id, Name, Department, ManagerId) values ('103', 'James', 'A', '101')
insert into Employee (Id, Name, Department, ManagerId) values ('104', 'Amy', 'A', '101')
insert into Employee (Id, Name, Department, ManagerId) values ('105', 'Anne', 'A', '101')
insert into Employee (Id, Name, Department, ManagerId) values ('106', 'Ron', 'B', '101')
The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id.
+------+----------+-----------+----------+ |Id |Name |Department |ManagerId | +------+----------+-----------+----------+ |101 |John |A |null | |102 |Dan |A |101 | |103 |James |A |101 | |104 |Amy |A |101 | |105 |Anne |A |101 | |106 |Ron |B |101 | +------+----------+-----------+----------+Given the Employee table, write a SQL query that finds out managers with at least 5 direct report. For the above table, your SQL query should return:
+-------+ | Name | +-------+ | John | +-------+Note:
No one would report to himself.
How does SQL Inner-Join Work?
The SQL Inner-Join (or often referred to as Join) can be easily illustrated using the following Venn Diagram:

sql-joins-venn-diagrams-inner-join
Two tables are joined and the result is the intersection of two tables.
select Name from Employee as A
inner join (
select ManagerId
from Employee
group by ManagerId
having count(1) >= 5
) as B on A.ID = B.ManagerId
As we can see, two tables (queries) are joined using the keyword inner join (case insensitive) or join in short. You also need to specify the columns that connect two tables using syntax On.
SQL Sub Query
As of this problem, we can also use the sub query to solve.
select Name from Employee where Id in ( select ManagerId from Employee group by ManagerId having count(ManagerId) >= 5 )
This works slightly differently, the IDs from a query are returned and are used as inputs to another query (more or less like the pipe).
–EOF (The Ultimate Computing & Technology Blog) —
推荐阅读:两个正方形的面积分别是4平方厘米和36平方厘米 原来两人共有多少钱 有一批商品需要装箱运输 三个学校共有多少人 屏蔽后台无用模块 提升wordpress运行效率 wordpress后台操作速度慢的原因及解决方法 如何禁止非管理员收到wordpress更新通知 Gravatar全球通用头像申请图文教程 如何使用wordpress全屏可视化编辑器 如何添加和删除wordpress用户角色
- 评论列表
-
- 添加评论