求梯形的腰长是多少米
- 时间:2020-06-13 17:16:40
- 分类:数学世界
- 阅读:155 次
一块等腰梯形的菜地,周长是42米,高是4米,面积是48平方米 ,求梯形的腰长是多少米?
数学题解答:梯形面积公式是:(上底+下底)×高÷2=梯形的面积,在知道梯形面积和高的情况下,可以利用公式倒推算出上底和下底的和:
48×2÷4=24(米)
而梯形的周长是42米,减去上、下底的和之后,得到的就是两腰的长度和,再除以2就算出了其中的一条腰:
(42-24)÷2=9(米)。答:梯形的腰长是9米。
也可以列方程来做,设梯形上、下底的和是x米。根据梯形面积公式列出方程:
x×4÷2=48
解得: x=24
接着用:(42-24)÷2=9(米)
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